Get line number with grep
WebNov 7, 2011 · To grep a pattern in a specific file, and get the matching lines: grep -n awk -F: ' { print $1 }' sort -u. or using cut as suggested by … WebJul 17, 2024 · How to Use grep to Display Filenames & Line Numbers Before Matching Lines. grep is a Linux utility commonly used for searching file contents, or any input …
Get line number with grep
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WebAug 26, 2011 · This will color the match as well for easy reading. Have you checked cat -n 'filename'. This will print the line numbers. cat will -n [umber] the lines and (filter) through grep looking only for lines with CONFIG_PM.... in them. the resulting output will be line number; the text of the line and the string.
WebMar 28, 2024 · To Display Line Numbers with grep Matches When grep prints results with many matches, it comes handy to see the line numbers. Append the -n operator to any grep command to show the line numbers. We will search for Phoenix in the current directory, show two lines before and after the matches along with their line numbers. grep -n -C 2 … Web/regexp/ Match lines matching the regular expression regexp. \cregexpc Match lines matching the regular expression regexp. The c may be any character. and FreeBSD sed man page: In a context address, any character other than a backslash (``\'') or newline character may be used to delimit the regular expression.
WebJun 9, 2016 · Depending on goals I like head or grep cat /var/log/syslog -n head -n 50 tail -n 10 will return lines 41 thru 50. or cat /var/log/syslog -n grep " 50" -b10 -a10 will show lines 40 thru 60. The problem with the grep method is that you have to use account for padding of the line numbers (notice the space) WebApr 10, 2024 · 0. I have a huge amount of data in the following format: [ [0] = 66, [1] = 12, [2] = 16, [3] = 36, [4] = -106, And I want to keep only the numbers that equals square brackets separated by spaces, so the output of the above example will be: 66 12 16 36 -106. The initial data was much more complex and I managed to reach this point but I can't ...
WebAug 2, 2006 · My first attempt involved grep -n 'hi' (the word 'hi will always be there) to get the line number before the line that I actually want (line 4). Extra Notes: -I am working in a bash script. -The file size is always variable, so I couldn't use head or tail. #file that I am evaluating Code: hello hey hi there <-line that i want how are you doing
WebAug 11, 2024 · You could want to create a command, and pass the id number and the file as parameters: #!/usr/bin/env bash sed -i "/id$1/s/state0/state1/" $2 invoking it like this: ./sed.sh 312 file Note: Always be careful with the -i switch: test first without it. Share Improve this answer Follow edited Aug 13, 2024 at 20:41 answered Aug 11, 2024 at 15:30 simlev the original buffet serumWebAdd a comment. 12. You can try the following command: git log --patch --color=always less +/searching_string. or using grep in the following way: git rev-list --all GIT_PAGER=cat xargs git grep 'search_string'. Run this command in the parent directory where you would like to search. Share. Improve this answer. the original buckwheatWebMar 15, 2015 · Yes, its possible with the -n option of grep. From man grep: -n, --line-number Prefix each line of output with the 1-based line number within its input file. For example, if you have a file named file.txt having: this is foo test and this is bar test Now the output of grep -n "test" file.txt: $ grep -n "test" file.txt 2:foo test 4:bar test the original buckwheat pillow companyWebNov 1, 2010 · This can be done by a regular expression, by field, or by piping each line through an external program. By default zindex creates an index of file.gz.zindex when asked to index file.gz. Example: create an index on lines matching a … the original buddha boardWebNov 23, 2009 · Using grep to extract line number. I'm trying to use grep to get the line number only. This is the command I'm using: grep -n "Content-Disposition: attachment" mbox The output I get is: 45:Content-Disposition: attachment; filename="test.txt" So now I just want to get the line number (45) from this output. the original buck rogersWebTo get only the line number (without the matching line), one may use cut: grep -n pattern file.txt cut -d : -f 1 Lines not containing a pattern are printed with grep -v: grep -v pattern file.txt Share Improve this answer Follow edited Feb 6, 2014 at 18:36 answered Jan 28, … the original buckle bootWebJun 24, 2024 · Get the first line only Pull out just the number without the matched text You can do the first one with head and the second with cut: $ cat sample.txt grep '^c' --line-number head -n 1 cut -d':' -f1 3 In your example output, you have some extra text - I'm not sure if this is important to you or not. the original bug catcher vacuum